NEET · Physics · STD 12 - 12. atoms
In hydrogen spectrum, the shortest wavelength in the Balmer series is \(\lambda\). The shortest wavelength in the Bracket series is \(........\,\lambda\)
- A \(16\)
- B \(2\)
- C \(4\)
- D \(9\)
Answer & Solution
Correct Answer
(C) \(4\)
Step-by-step Solution
Detailed explanation
Shortest wavelength in Balmer series when transition of \(e^{-}\)from \(\infty\) to \(n=2\) \(\because \frac{1}{\lambda}= Rz ^2\left[\frac{1}{2^2}-\frac{1}{\infty^2}\right]\)
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