NEET · Physics · STD 11 - 1. units,dimensions and measurement
In a vernier callipers, 20 VSD coincide with 16 MSD (each division of length 1 mm). The least count of the vernier callipers is :
- A 0.2 cm
- B 0.01 cm
- C 0.02 cm
- D 0.1 cm
Answer & Solution
Correct Answer
(C) 0.02 cm
Step-by-step Solution
Detailed explanation
(C) 0.02 cm
Given \(20 VSD =16 MSD\).
\(1 VSD=\frac{16}{20} MSD=0.8 MSD .\)
Least count is given by \(1 MSD -1 VSD\).
Least count \(=1 MSD -0.8 MSD =0.2 MSD\).
Since \(1 MSD =1 mm\), we get Least count \(=0.2 mm\).
Converting to cm, Least count \(=0.02 cm\).
Given \(20 VSD =16 MSD\).
\(1 VSD=\frac{16}{20} MSD=0.8 MSD .\)
Least count is given by \(1 MSD -1 VSD\).
Least count \(=1 MSD -0.8 MSD =0.2 MSD\).
Since \(1 MSD =1 mm\), we get Least count \(=0.2 mm\).
Converting to cm, Least count \(=0.02 cm\).
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