NEET · Physics · STD 12 - 8. Electromagnetic waves
In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of \(2.0 \times 10^{10}\,Hz\) and amplitude \(48\,Vm ^{-1}\). Then the amplitude of oscillating magnetic field is : (Speed of light in free space \(=3 \times 10^8\,m s ^{-1}\))
- A \(1.6 \times 10^{-6}\,T\)
- B \(1.6 \times 10^{-9}\,T\)
- C \(1.6 \times 10^{-8}\,T\)
- D \(1.6 \times 10^{-7}\,T\)
Answer & Solution
Correct Answer
(D) \(1.6 \times 10^{-7}\,T\)
Step-by-step Solution
Detailed explanation
\(C =\frac{ E _0}{ B _0}\) \(B _0=\frac{ E _0}{ C }\)
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