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NEET · Physics · STD 11 - 7. gravitation

Imagine earth to be a solid sphece of mass \(M\) and radius \(R\). If the value of acceleration due to gravity at a depth d below earth's surface is same as its value at a height \(h\) above its surface and equal to \(\frac{g}{4}\) (where \(g\) is the value of acceleration due to gravity on the surface of earth), the ratio of \(\frac{h}{d}\) will be

  1. A \(\frac{4}{3}\)
  2. B \(\;\frac{3}{2}\)
  3. C \(\;\frac{2}{3}\)
  4. D \(1\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{4}{3}\)

Step-by-step Solution

Detailed explanation

\(\Rightarrow g(h)=\frac{g}{\left(1+\frac{h}{R}\right)^2}\) \(\therefore \frac{g}{4}=\frac{g}{\left(1+\frac{h}{R}\right)^2}\)
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