NEET · Physics · STD 11 - 1. units,dimensions and measurement
If \(\mathrm{E}\) and \(\mathrm{G}\) respectively denote energy and gravitational constant, then \(\frac{\mathrm{E}}{\mathrm{G}}\) has the dimensions of :
- A \([\mathrm{M}]\left[\mathrm{L}^{-1}\right]\left[\mathrm{T}^{-1}\right]\)
- B \(\left[\mathrm{M}^{2}\right]\left[\mathrm{L}^{-1}\right]\left[\mathrm{T}^{0}\right]\)
- C \([\mathrm{M}]\left[\mathrm{L}^{0}\right]\left[\mathrm{T}^{0}\right]\)
- D \(\left[\mathrm{M}^{2}\right]\left[\mathrm{L}^{-2}\right]\left[\mathrm{T}^{-1}\right]\)
Answer & Solution
Correct Answer
(B) \(\left[\mathrm{M}^{2}\right]\left[\mathrm{L}^{-1}\right]\left[\mathrm{T}^{0}\right]\)
Step-by-step Solution
Detailed explanation
\(E=\) energy \(=\left[M L^{2} T^{-2}\right]\) \(G=\) Gravitational constant \(=\left[\mathrm{M}^{-1} L^{3} \mathrm{~T}^{-2}\right]\)
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