NEET · Physics · STD 11 - 6. system of particles and rotational motion
From a disc of radius \(R\) and mass \(M,\) a circular hole of diameter \(R,\) whose rim passes through the centre is cut. What is the moment of inertia of the remaining part of the disc about a perpendicular axis, passing through the centre?
- A \(\frac{{13M{R^2}}}{{32}}\)
- B \(\;\frac{{11M{R^2}}}{{32}}\)
- C \(\;\frac{{9M{R^2}}}{{32}}\)
- D \(\;\frac{{15M{R^2}}}{{32}}\)
Answer & Solution
Correct Answer
(A) \(\frac{{13M{R^2}}}{{32}}\)
Step-by-step Solution
Detailed explanation
Mass per unit area of disc \(= \frac{M}{{\pi {R^2}}}\) Mass of removed portion of disc,
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