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NEET · Physics · STD 12 - 8. Electromagnetic waves
For a transparent medium relative permeablity and permittlivity, \(\mu_{\mathrm{r}}\) and \(\epsilon_{\mathrm{r}}\) are \(1.0\) and \(1.44\) respectively. The velocity of light in this medium would be,
- A \(2.5 \times 10^{8} \;\mathrm{m} / \mathrm{s}\)
- B \(3 \times 10^{8} \;\mathrm{m} / \mathrm{s}\)
- C \(2.08 \times 10^{8} \;\mathrm{m} / \mathrm{s}\)
- D \(4.32 \times 10^{8} \;\mathrm{m} / \mathrm{s}\)
Answer & Solution
Correct Answer
(A) \(2.5 \times 10^{8} \;\mathrm{m} / \mathrm{s}\)
Step-by-step Solution
Detailed explanation
\(v=\frac{1}{\sqrt{\mu} \epsilon}=\frac{1}{\sqrt{\mu_{\mathrm{r}} \in_{\mathrm{r}} \mu_{0} \epsilon_{0}}}\)\(=\frac{3 \times 10^{8}}{\sqrt{1.44}}=\frac{30}{12} \times 10^{8}\)\(=2.5 \times 10^{8} \;\mathrm{ms}^{-1}\)
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