NEET · Physics · STD 12 - 14. Semicondutor electronics
Consider the junction diode as ideal. The value of current flowing through \(AB\) is
- A \(10^{-2}\;A\)
- B \(10^{-1}\;A\)
- C \(10^{-3}\;A\)
- D \(0\;A\)
Answer & Solution
Correct Answer
(A) \(10^{-2}\;A\)
Step-by-step Solution
Detailed explanation
Here, the \(p-n\) junction diode is forwarc biased, hence it offers zero resistance \(\therefore {{I}_{AB}}=\frac{{{V}_{A}}-{{V}_{B}}}{{{R}_{AB}}}=\) \(\frac{4\text{V}-(-6\text{V})}{1\text{k}\Omega }=\) \(\frac{10}{1000}\text{A}={{10}^{-2}}\text{A}\)
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