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NEET · Physics · STD 12 - 14. Semicondutor electronics
An \(LED\) is constructed from a \(p-n\) junction diode using \(GaAsP\). The energy gap is \(1.9\; eV\). The wavelength of the light emitted will be equal to
- A \(10.4 \times 10^{-26}\; \mathrm{m}\)
- B \(654 \;nm\)
- C \(654 \;\mathring A\)
- D \(654 \times 10^{-11} \;\mathrm{m}\)
Answer & Solution
Correct Answer
(B) \(654 \;nm\)
Step-by-step Solution
Detailed explanation
\(\lambda=\frac{1240 \mathrm{nm}}{1.9}=652.6 \mathrm{nm} \simeq 654\; \mathrm{nm}\)
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