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NEET · Physics · STD 12 - 14. Semicondutor electronics

An \(LED\) is constructed from a \(p-n\) junction diode using \(GaAsP\). The energy gap is \(1.9\; eV\). The wavelength of the light emitted will be equal to

  1. A \(10.4 \times 10^{-26}\; \mathrm{m}\)
  2. B \(654 \;nm\)
  3. C \(654 \;\mathring A\)
  4. D \(654 \times 10^{-11} \;\mathrm{m}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(654 \;nm\)

Step-by-step Solution

Detailed explanation

\(\lambda=\frac{1240 \mathrm{nm}}{1.9}=652.6 \mathrm{nm} \simeq 654\; \mathrm{nm}\)