NEET · Physics · STD 12 -7. Alternating current
An inductor \(20\,\, mH,\) a capacitor \(100\, \mu F\) and a resistor \(50 \,\,\Omega\) are connected in series across a source of emf, \(V=10 sin 314 \,t .\) The power loss in the circuit is ......\(W\)
- A \(0.79\)
- B \(0.43\)
- C \(1.13\)
- D \(2.74\)
Answer & Solution
Correct Answer
(A) \(0.79\)
Step-by-step Solution
Detailed explanation
Impedance \(Z\) in an \(ac\) circuit is \(Z=\sqrt{R^{2}+\left(X_{C}-X_{L}\right)^{2}} ;\) where \(X_{C}=\) capacitive reactance and \(X_{L}=\) inductive reactance.
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