NEET · Physics · STD 12 - 11. Dual nature of radiation and matter
An electron is accelerated through a potential difference of \(10,000\; \mathrm{V}\). Its de Broglie wavelength is, (nearly): \(\left(\mathrm{m}_{\mathrm{e}}=9 \times 10^{-31}\;\mathrm{kg}\right)\)
- A \(12.2 \times 10^{-13} \;\mathrm{m}\)
- B \(12.2 \times 10^{-12} \;\mathrm{m}\)
- C \(12.2 \times 10^{-14} \;\mathrm{m}\)
- D \(12.2\; \mathrm{nm}\)
Answer & Solution
Correct Answer
(B) \(12.2 \times 10^{-12} \;\mathrm{m}\)
Step-by-step Solution
Detailed explanation
\(\lambda=\sqrt{\frac{150}{V}} \mathring A\) \(\lambda=\sqrt{\frac{150}{10^{4}}} \mathring A\)\(=12.27 \times 10^{-12} \;\mathrm{m}\)
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