NEET · Physics · STD 11 - 5. work,energy,power and collision
An electric lift with a maximum load of \(2000\,kg\) (lift+ passengers) is moving up with a constant speed of \(1.5\,ms ^{-1}\). The frictional force opposing the motion is \(3000\,N\). The minimum 10.Power delivered by the motor to the lift in watts is: \(\left(g=10\,ms^{-2}\right)\)
- A \(20000\)
- B \(34500\)
- C \(23500\)
- D \(23000\)
Answer & Solution
Correct Answer
(B) \(34500\)
Step-by-step Solution
Detailed explanation
Constant velocity \(\Rightarrow a =0\) \(\Rightarrow T = W + f\)
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