NEET · Physics · STD 12 - 4. Moving charges and magnetism
An arrangement of three parallel straight wires placed perpendicular to plane of paper carrying same current \('I'\) along the same direction as shown in figure. Magnitude of force per unit length on the middle wire \('B'\) is given by

- A \(\frac{{2{\mu _0}{I^2}}}{{\pi d}}\)
- B \(\frac{{\sqrt 2 {\mu _0}{I^2}}}{{\pi d}}\)
- C \(\;\frac{{{\mu _0}{I^2}}}{{\sqrt 2 \pi d}}\)
- D \(\;\frac{{{\mu _0}{I^2}}}{{2\pi d}}\)
Answer & Solution
Correct Answer
(C) \(\;\frac{{{\mu _0}{I^2}}}{{\sqrt 2 \pi d}}\)
Step-by-step Solution
Detailed explanation
Force between wires \(A\) and \(B\) \(=\) force between wires \(B\) and \(C\) \(\therefore \quad F_{B C}=F_{A B}=\frac{\mu_{0} I^{2} l}{2 \pi d}\)
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