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NEET · Physics · STD 12 - 4. Moving charges and magnetism

An arrangement of three parallel straight wires placed perpendicular to plane of paper carrying same current \('I'\) along the same direction as shown in figure. Magnitude of force per unit length on the middle wire \('B'\) is given by 

  1. A \(\frac{{2{\mu _0}{I^2}}}{{\pi d}}\)
  2. B \(\frac{{\sqrt 2 {\mu _0}{I^2}}}{{\pi d}}\)
  3. C \(\;\frac{{{\mu _0}{I^2}}}{{\sqrt 2 \pi d}}\)
  4. D \(\;\frac{{{\mu _0}{I^2}}}{{2\pi d}}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\;\frac{{{\mu _0}{I^2}}}{{\sqrt 2 \pi d}}\)

Step-by-step Solution

Detailed explanation

Force between wires \(A\) and \(B\) \(=\) force between wires \(B\) and \(C\) \(\therefore \quad F_{B C}=F_{A B}=\frac{\mu_{0} I^{2} l}{2 \pi d}\)
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