NEET · Physics · STD 12 - 3. current electricity
A wire of resistance R is cut into 8 equal pieces. From these pieces two equivalent resistances are made by adding four of these together in parallel. Then these two sets are added in series. The net effective resistance of the combination is :
- A \(\frac{R}{64}\)
- B \(\frac{ R }{32}\)
- C \(\frac{R}{16}\)
- D \(\frac{ R }{8}\)
Answer & Solution
Correct Answer
(C) \(\frac{R}{16}\)
Step-by-step Solution
Detailed explanation
\(\text {Resistance of each part }=R / 8\)
\(R_{eq}=\frac{1}{4}(R / 8)+\frac{1}{4}(R / 8)=\frac{R}{16}\)
\(R_{eq}=\frac{1}{4}(R / 8)+\frac{1}{4}(R / 8)=\frac{R}{16}\)
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