NEET · Physics · STD 11- 8. mechanical properties of solids
A wire of length \(L,\) area of cross section \(A\) is hanging from a fixed support. The length of the wire changes to \(L_{1}\) when mass \(M\) is suspended from its free end. The expression for Young's modulus is
- A \(\frac{ MgL }{ A \left( L _{1}- L \right)}\)
- B \(\frac{ MgL _{1}}{ AL }\)
- C \(\frac{ Mg \left( L _{1}- L \right)}{ AL }\)
- D \(\frac{ MgL }{ AL _{1}}\)
Answer & Solution
Correct Answer
(A) \(\frac{ MgL }{ A \left( L _{1}- L \right)}\)
Step-by-step Solution
Detailed explanation
\(Y=\frac{F L }{A \Delta L}=\frac{M g L}{A\left(L_{1}-L\right)}\)
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