NEET · Physics · STD 12 - 4. Moving charges and magnetism
A very long conducting wire is bent in a semicircular shape from \(A\) to \(B\) as shown in figure. The magnetic field at point \(P\) for steady current configuration is given by:

- A \(\frac{\mu_0 i }{4 R }\left[1-\frac{2}{\pi}\right]\) pointed into the page
- B \(\frac{\mu_0 i }{4 R }\) pointed into the page
- C \(\frac{\mu_0 i }{4 R }\) pointed away from the page
- D \(\frac{\mu_0 i }{4 R }\left[1-\frac{2}{\pi}\right]\) pointed away from page
Answer & Solution
Correct Answer
(D) \(\frac{\mu_0 i }{4 R }\left[1-\frac{2}{\pi}\right]\) pointed away from page
Step-by-step Solution
Detailed explanation
\(B =\frac{\mu_0}{4 \pi} \frac{I}{R}(\pi)-\frac{\mu_0}{4 \pi} \frac{2 I }{ R }\) \(=\frac{\mu_0 I }{4 R }\left[1-\frac{2}{\pi}\right] \text { outward i.e away from page. }\)
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