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NEET · Physics · STD 12 - 4. Moving charges and magnetism
A uniform magnetic field of \(0.3\; T\) is established along the positive \(Z\) -direction. A rectangular loop in \(XY\) plane of sides \(10 \;cm\) and \(5 \;cm\) carries a current of \(I =12\; A\) as shown. The torque on the loop is

- A \(-1.8 \times 10^{-2}\)\(\hat j\;Nm\)
- B \(0\)
- C \(-1.8 \times 10^{-2}\) \(\hat i\;Nm\)
- D \(+1.8 \times 10^{-2}\) \(\hat i\;Nm\)
Answer & Solution
Correct Answer
(B) \(0\)
Step-by-step Solution
Detailed explanation
\(\vec{\tau}= NIA \times \overline{ B }\) Here \(\overrightarrow{ A } \| \overrightarrow{ B }\)
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