NEET · Physics · STD 11 - 13. oscillations
A spring of force constant \(k\) is cut into lengths of ratio \(1:2:3\) . They are connected in series and the new force constant is \(k'\) . Then they are connected in parallel and force constant is \(k''\) . Then \(k':k''\) is
- A \(1:11\)
- B \(1:14\)
- C \(1:16\)
- D \(1:9\)
Answer & Solution
Correct Answer
(A) \(1:11\)
Step-by-step Solution
Detailed explanation
Let us assume, the length of spring be \(l\). When we cut the spring into ratio of length \(1: 2: 3,\) we
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