NEET · Physics · STD 11 - 13. oscillations
A spring is stretched by \(5 \,\mathrm{~cm}\) by a force \(10 \,\mathrm{~N}\). The time period of the oscillations when a mass of \(2 \,\mathrm{~kg}\) is suspended by it is :(in \(s\))
- A \(0.0628\)
- B \(6.28\)
- C \(3.14\)
- D \(0.628\)
Answer & Solution
Correct Answer
(D) \(0.628\)
Step-by-step Solution
Detailed explanation
\(\mathrm{F}=\mathrm{K} \mathrm{x}\) \(10=\mathrm{K} \times 0.05\)
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