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NEET · Physics · STD 11 - 6. system of particles and rotational motion
A solld cylinder of mass \(2 \;\mathrm{kg}\) and radius \(50 \;\mathrm{cm}\) rolls up an inclined plane of angle inclination \(30^{\circ}\). The centre of mass of cyllnder has speed of \(4 \;\mathrm{m} / \mathrm{s}\). The distance travelled by the cyllinder on the incline surface will be ......\(m\)
- A \(2.2\)
- B \(1.6\)
- C \(1.2\)
- D \(2.4\)
Answer & Solution
Correct Answer
(D) \(2.4\)
Step-by-step Solution
Detailed explanation
\(\frac{1}{2} m v^{2}\left(1+\frac{K^{2}}{R^{2}}\right)=m g h \Rightarrow 8\left(1+\frac{1}{2}\right)=10 h \) \(\Rightarrow h=1.2 \mathrm{m}\)
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