NEET · Physics · STD 11 - 9.2 surface tension
A soap bubble, having radius of \(1\; \mathrm{mm}\), is blown from a detergent solution having a surface tension of \(2.5 \times 10^{-2}\; N / m\). The pressure inside the bubble equals at a point \(Z_{0}\) below the free surface of water in a container. Taking \(g=10\; \mathrm{m} / \mathrm{s}^{2}\) density of water \(=10^{3} \;\mathrm{kg} / \mathrm{m}^{3},\) the value of \(\mathrm{Z}_{0}\) is......\(cm\)
- A \(100\)
- B \(10\)
- C \(1\)
- D \(0.5 \)
Answer & Solution
Correct Answer
(C) \(1\)
Step-by-step Solution
Detailed explanation
\(P=P_{0}+\rho g Z_{0}\ldots(i)\) Also, \(\mathrm{P}=\mathrm{P}_{0}+\frac{4 \mathrm{T}}{\mathrm{R}}\ldots\) (ii)
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