NEET · Physics · STD 11 - 2. motion in straight line
A small block slides down on a smooth inclined plane, starting from rest at time \(t=0 .\) Let \(S_{n}\) be the distance travelled by the block in the interval \(\mathrm{t}=\mathrm{n}-1\) to \(\mathrm{t}=\mathrm{n} .\) Then, the ratio \(\frac{\mathrm{S}_{\mathrm{n}}}{\mathrm{S}_{\mathrm{n}+1}}\) is
- A \(\frac{2 n-1}{2 n}\)
- B \(\frac{2 n-1}{2 n+1}\)
- C \(\frac{2 n+1}{2 n-1}\)
- D \(\frac{2 n}{2 n-1}\)
Answer & Solution
Correct Answer
(B) \(\frac{2 n-1}{2 n+1}\)
Step-by-step Solution
Detailed explanation
\(\frac{s_{n}}{S_{n+1}}=\frac{\frac{a}{2}(2 n-1)}{\frac{a}{2}(2(n+1)-1)}=\frac{2 n-1}{2 n+2-1}=\frac{2 n-1}{2 n+1}\)
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