NEET · Physics · STD 12 - 3. current electricity
A set of \(n\) equal resistors, of value \(R\) each, are connected in series to a battery of emf \(E\) and internal resistance \(R.\) The current drawn is \(I.\) Now, the \(n\) resistors are connected in parallel to the same battery. Then the current drawn from battery becomes \(10\,I.\) The value of \(n\) is
- A \(10\)
- B \(11\)
- C \(9\)
- D \(20\)
Answer & Solution
Correct Answer
(A) \(10\)
Step-by-step Solution
Detailed explanation
Current drawn from a battery when \(n\) resistors are connected in series is \(I=\frac{E}{n R+R}\) .....\((i)\)
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