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NEET · Physics · STD 11 - 7. gravitation

A satellite is orbiting just above the surface of the earth with period \(T\). If \(d\) is the density of the earth and \(G\) is the universal constant of gravitation, the quantity \(\frac{3 \pi}{G d}\) represents :

  1. A \(\sqrt{T}\)
  2. B \(T\)
  3. C \(T^2\)
  4. D \(T^3\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(T^2\)

Step-by-step Solution

Detailed explanation

\(T=\frac{2 \pi}{\sqrt{G M}} r^{3 / 2} \Rightarrow T^2=\frac{4 \pi^2 R^3}{G\left(\frac{4}{3} \pi R^3 d\right)} \quad( r = R )\) \(T ^2=\frac{3 \pi}{ Gd }\)