NEET · Physics · STD 11 - 14. waves and sound
A pipe open at both ends has a fundamental frequency \(f\) in air. The pipe is now dipped vertically in a water drum to half of its length. The fundamental frequency of the air column is now equal to:
- A \(\frac{f}{2}\)
- B \(f\)
- C \(\frac{3 f}{2}\)
- D \(2 f\)
Answer & Solution
Correct Answer
(B) \(f\)
Step-by-step Solution
Detailed explanation
For open pipe
\(f =\frac{ v }{2 \ell}\)
When half of its length is dipped in water, Now it is COP.
\(f ^{\prime} =\frac{ V }{4(\ell / 2)} \)
\( f ^{\prime} =\frac{ V }{2 \ell} \)
\( f ^{\prime} = f\)
\(f =\frac{ v }{2 \ell}\)
When half of its length is dipped in water, Now it is COP.
\(f ^{\prime} =\frac{ V }{4(\ell / 2)} \)
\( f ^{\prime} =\frac{ V }{2 \ell} \)
\( f ^{\prime} = f\)
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