NEET · Physics · STD 11 - 13. oscillations
A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is \(20\; m/s^2\) at a distance of \(5\; m\) from the mean position. The time period of oscillation is
- A \(2\pi\;s\)
- B \(\pi\;s\)
- C \(1\;s\)
- D \(2\;s\)
Answer & Solution
Correct Answer
(B) \(\pi\;s\)
Step-by-step Solution
Detailed explanation
Magnitude of acceleration of a particle moving in a \(SHM\) is, \(|a|=\omega^{2} y ;\) where \(y\) is amplitude. \(\Rightarrow \quad 20=\omega^{2}(5) \Rightarrow \omega=2 \mathrm{rad} \mathrm{s}^{-1}\)
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