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NEET · Physics · STD 12 - 2. Electric potential and capacitance
A parallel plate capacitor is to be designed, using a dielectric of dielectric constant \(5\), so as to have a dielectric strength of \(10^9\;Vm^{-1}\) . If the voltage rating of the capacitor is \(12\;kV\), the minimum area of each plate required to have a capacitance of \(80\;pF\) is
- A \(10.5 \times 10^{-6} \;m ^2\)
- B \(25.0 \times 10^{-5}\; m ^2\)
- C \(12.5 \times 10^{-5}\; m ^2\)
- D \(21.7 \times 10^{-6} \;m ^2\)
Answer & Solution
Correct Answer
(D) \(21.7 \times 10^{-6} \;m ^2\)
Step-by-step Solution
Detailed explanation
\(V=E d\) \(\therefore d=\frac{V}{E}\)
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