NEET · Physics · STD 12 - 2. Electric potential and capacitance
A parallel plate capacitor has a uniform electric field ' \(\overrightarrow{\mathrm{E}}\) ' in the space between the plates. If the distance between the plates is ' \(\mathrm{d}\) ' and the area of each plate is ' \(A\) ', the energy stored in the capacitor is : \(\left(\varepsilon_{0}=\right.\) permittivity of free space)
- A \(\frac{1}{2} \varepsilon_{0} \mathrm{E}^{2}\)
- B \(\varepsilon_{0} \mathrm{EAd}\)
- C \(\frac{1}{2} \varepsilon_{0} E^{2} \mathrm{Ad}\)
- D \(\frac{\mathrm{E}^{2} \mathrm{Ad}}{\varepsilon_{0}}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{2} \varepsilon_{0} E^{2} \mathrm{Ad}\)
Step-by-step Solution
Detailed explanation
Energy \(=\) Energy density \(\times\) volume \(=\frac{1}{2} \varepsilon_{0} E^{2} A d\)
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