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NEET · Physics · STD 12 - 13. Nuclei

A nucleus with mass number \(240\) breaks into two fragments each of mass number \(120 ,\) the binding energy per nucleon of unfragmented nuclei is \(7.6 \,\mathrm{MeV}\) while that of fragments is \(8.5\, \mathrm{MeV}\). The total gain in the Binding Energy in the process is : (In \(\mathrm{MeV}\))

  1. A \(0.9\)
  2. B \(9.4\)
  3. C \(804\)
  4. D \(216\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(216\)

Step-by-step Solution

Detailed explanation

\(\mathrm{X}^{240} \rightarrow \mathrm{Y}^{120} \rightarrow \mathrm{Z}^{120}\) given binding energy per nucleon of \(X, Y \& Z\) are