NEET · Physics · STD 12 - 13. Nuclei
A nucleus with mass number \(240\) breaks into two fragments each of mass number \(120 ,\) the binding energy per nucleon of unfragmented nuclei is \(7.6 \,\mathrm{MeV}\) while that of fragments is \(8.5\, \mathrm{MeV}\). The total gain in the Binding Energy in the process is : (In \(\mathrm{MeV}\))
- A \(0.9\)
- B \(9.4\)
- C \(804\)
- D \(216\)
Answer & Solution
Correct Answer
(D) \(216\)
Step-by-step Solution
Detailed explanation
\(\mathrm{X}^{240} \rightarrow \mathrm{Y}^{120} \rightarrow \mathrm{Z}^{120}\) given binding energy per nucleon of \(X, Y \& Z\) are
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