NEET · Physics · STD 12 - 14. Semicondutor electronics
A \(npn\) transistor is connected in common emitter configuration in a given amplifier. A load resistance of \(800 \,\,\Omega\) is connected in the collector circuit and the voltage drop across it is \(0.8\,\, V.\) If the current amplification factor is \(0.96\) and the input resistance of the circuit is \(192 \,\,\Omega\), the voltage gain and the power gain of the amplifier will respectively be
- A \(3.69,3.84\)
- B \(4,4\)
- C \(4,3.69\)
- D \(4,3.84\)
Answer & Solution
Correct Answer
(D) \(4,3.84\)
Step-by-step Solution
Detailed explanation
\(\text { Here, } R_{0}=800 \Omega, R_{i}=192 \Omega\) current gain, \(\beta=0.96\)
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