NEET · Physics · STD 12 - 4. Moving charges and magnetism
A metallic rod of mass per unit length \(0.5\; kg\; m^{-1}\) is lying horizontally on a smooth inclined plane which makes an angle of \(30^o\) with the horizontal. The rod is not allowed to slide down by flowing a current through it when a magnetic field of induction \(0.25\; T\) is acting on it in the vertical direction. The current flowing in the rod to keep it stationary is.....\(A\)
- A \(7.14 \)
- B \(\;\)\(5.98 \)
- C \(11.32 \)
- D \(\;\)\(14.76 \)
Answer & Solution
Correct Answer
(C) \(11.32 \)
Step-by-step Solution
Detailed explanation
For equilibrium, \(m g \sin 30^{\circ}=I l B \cos 30^{\circ}\)
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