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NEET · Physics · STD 11 - 9.1 fluid mechanics
A metal block of base area \(0.2\; m ^{2}\) is connected to a \(0.02\; kg\) mass via a string that passes over an ideal pulley as shown in figure. A liquid film of thickness \(0.6\; mm\) is placed between the block and the table. When released the block moves to the right with a constant speed of \(0.17\; m / s\). The co-efficient of viscosity of the liquid is
- A \(3.45 \times 10^{-2} Pa{-s}\)
- B \(3.45 \times 10^{-3} Pa{-s}\)
- C \(3.45 \times 10^{2} Pa{-s}\)
- D \(3.45 \times 10^{3} Pa{-s}\)
Answer & Solution
Correct Answer
(B) \(3.45 \times 10^{-3} Pa{-s}\)
Step-by-step Solution
Detailed explanation
Shear force, \(F=T=m g=0.01\; kg \times 10\; m s ^{-2}=0.1\; N\) Shear stress on the fluid \(=\frac{F}{A}=\frac{0.1\; N }{0.1 \;m ^{2}}\)
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