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NEET · Physics · STD 12 - 4. Moving charges and magnetism

A long straight wire of radius \(a\) carries a steady current \(I.\) The current is uniformly distributed over its cross-section. The ratio of  the magnetic fields \(B\) and \(B',\) at radial distances \(\frac{a}{2}\) and \(2a\) respectively, from the axis of the wire is 

  1. A \(\frac{1}{2}\)
  2. B \(1\)
  3. C \(4\)
  4. D \(\;\frac{1}{4}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(1\)

Step-by-step Solution

Detailed explanation

Magnetic field at a point inside the wire at distance \(r\left(=\frac{a}{2}\right)\) from the axis of wire is \(B=\frac{\mu_{0} I}{2 \pi a^{2}} r=\frac{\mu_{0} I}{2 \pi a^{2}} \times \frac{a}{2}=\frac{\mu_{0} I}{4 \pi a}\)