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NEET · Physics · STD 11 - 6. system of particles and rotational motion

A light rod of length \(l\) has two masses \(m_1\) and \(m_2\) attached to its two ends. The moment of inertia of the system about an axis perpendicular to the rod and passing through the centre of mass is 

  1. A \((m_1+m_2)l^2\)
  2. B \(\sqrt {{m_1}{m_2}} {l^2}\)
  3. C \(\frac{{{m_1}{m_2}}}{{{m_1} + {m_2}}}{l^2}\)
  4. D \(\;\frac{{{m_1} + {m_2}}}{{{m_1}{m_2}}}{l^2}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{{{m_1}{m_2}}}{{{m_1} + {m_2}}}{l^2}\)

Step-by-step Solution

Detailed explanation

Here,\({l_1} + {l_2} = l\) Center of mass of the system,
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