NEET · Physics · STD 11 - 4.1 newtons laws of motion
A horizontal force \(10 \mathrm{~N}\) is applied to a block \(A\) as shown in figure. The mass of blocks \(A\) and \(B\) are \(2 \mathrm{~kg}\) and \(3 \mathrm{~kg}\) respectively. The blocks slide over a frictionless surface. The force exerted by block \(A\) on block \(B\) is :

- A \(4 \mathrm{~N}\)
- B \(6 \mathrm{~N}\)
- C \(10 \mathrm{~N}\)
- D Zero
Answer & Solution
Correct Answer
(B) \(6 \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
\(F=\left(M_1+M_2\right) a\) \(a=\frac{10}{2+3}=2 \mathrm{~ms}^{-2}\)
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