NEET · Physics · STD 12 - 11. Dual nature of radiation and matter
A galvanometer of resistance \(100 \Omega\) gives full scale deflection for a current of 1 mA. It is converted into an ammeter of range 0−10 A. The shunt required is :
- A 0.01 Ω
- B 0.10 Ω
- C 1.0 Ω
- D 0.001 Ω
Answer & Solution
Correct Answer
(A) 0.01 Ω
Step-by-step Solution
Detailed explanation
(A) \(0.01 \Omega\)
Given \(G=100 \Omega, I_g=1 mA=10^{-3} A\), and \(I=10 A\).
The shunt resistance \(S\) required to convert a galvanometer into an ammeter is given by:
\(S=\frac{I_g G}{I-I_g}\)
Substituting the values:
\(S=\frac{10^{-3} \times 100}{10-10^{-3}}\)
Since \(10 \gg 10^{-3}\), we can approximate \(10-10^{-3} \approx 10\).
\(S \approx \frac{0.1}{10}=0.01 \Omega\)
Given \(G=100 \Omega, I_g=1 mA=10^{-3} A\), and \(I=10 A\).
The shunt resistance \(S\) required to convert a galvanometer into an ammeter is given by:
\(S=\frac{I_g G}{I-I_g}\)
Substituting the values:
\(S=\frac{10^{-3} \times 100}{10-10^{-3}}\)
Since \(10 \gg 10^{-3}\), we can approximate \(10-10^{-3} \approx 10\).
\(S \approx \frac{0.1}{10}=0.01 \Omega\)
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