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NEET · Physics · STD 12 - 3. current electricity
A filament bulb \((500 \,W,\,\, 100 \,V)\) is to be used in a \(230\, V\) main supply. When a resistance \(R\) is connected in series, it works perfectly and the bulb consumes \(500\,W.\) The value of \(R\) is .................. \(\Omega\)
- A \(26\)
- B \(13\)
- C \(230\)
- D \(46\)
Answer & Solution
Correct Answer
(A) \(26\)
Step-by-step Solution
Detailed explanation
Resistance of bulb, \(R_{B}=\frac{V^{2}}{P}=\frac{(100)^{2}}{500}=20\, \Omega\) Power of the bulb in the circuit,
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