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NEET · Physics · STD 12 - 9. Ray optics and optical instruments
A double convex lens has focal length \(25\; \mathrm{cm}\). The radius of curvature of one of the surfaces is double of the other. Find the radii If the refractive index of the material of the lens is \(1.5 \)
- A \(100 \;\mathrm{cm}, 50\; \mathrm{cm}\)
- B \(25\; \mathrm{cm}, 50\; \mathrm{cm}\)
- C \(18.75\; \mathrm{cm}, 37.5 \;\mathrm{cm}\)
- D \( 50\; \mathrm{cm}, 100\; \mathrm{cm}\)
Answer & Solution
Correct Answer
(C) \(18.75\; \mathrm{cm}, 37.5 \;\mathrm{cm}\)
Step-by-step Solution
Detailed explanation
\(\frac{1}{f}=\left(\frac{\mu_{2}-\mu_{1}}{\mu_{1}}\right)\left(\frac{1}{R_{1}}-\frac{1}{R_{2}}\right)\) \(\Rightarrow \frac{1}{25}=\left(\frac{1.5-1}{1}\right)\left(\frac{1}{R}-\frac{1}{(-2 R)}\right) \)
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