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NEET · Physics · STD 12 -6. Electromagnetic induction
A cycle wheel of radius \(0.5 \;\mathrm{m}\) is rotated with constant angular velocity of \(10 \;\mathrm{rad} / \mathrm{s}\) In a region of magnetic field of \(0.1\; T\) which is perpendicular to the plane of the wheel. The \(EMF\) generated between its centre and the rim is.....\(V\)
- A \(0.25\)
- B \(0.125\)
- C \(0.5\)
- D \(0\)
Answer & Solution
Correct Answer
(B) \(0.125\)
Step-by-step Solution
Detailed explanation
\(\mathrm{E}=\frac{\mathrm{B} \omega \ell^{2}}{2}=\frac{0.1(10)(0.5)^{2}}{2}=0.125 \mathrm{V}\)
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