NEET · Physics · STD 11 - 10.2 transmission of heat
A cup of coffee cools from \(90^{\circ} \mathrm{C}\) to \(80^{\circ} \mathrm{C}\) in \(\mathrm{t}\) minutes, when the room temperature is \(20^{\circ} \mathrm{C}\). The time taken by a similar cup of coffee to cool from \(80^{\circ} \mathrm{C}\) to \(60^{\circ} \mathrm{C}\) at a room temperature same at \(20^{\circ} \mathrm{C}\) is :
- A \(\frac{13}{10} \mathrm{t}\)
- B \(\frac{13}{5} \mathrm{t}\)
- C \(\frac{10}{13} \mathrm{t}\)
- D \(\frac{5}{13} \mathrm{t}\)
Answer & Solution
Correct Answer
(B) \(\frac{13}{5} \mathrm{t}\)
Step-by-step Solution
Detailed explanation
\(\frac{d T}{d t}=K\left(T_{a v}-T_{0}\right)\) \(\frac{10}{t}=K(85-20)\)
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