NEET · Physics · STD 11 - 3.2 motion in plane
A cricket ball is thrown by a player at a speed of \(20\,m / s\) in a direction \(30^{\circ}\) above the horizontal. The maximum height attained by the ball during its motion is \(........\,m\) \(\left( g =10\,m / s ^2\right)\)
- A \(5\)
- B \(10\)
- C \(20\)
- D \(25\)
Answer & Solution
Correct Answer
(A) \(5\)
Step-by-step Solution
Detailed explanation
\(H =\frac{ u ^2 \sin ^2 \theta}{2 g }=\frac{(20)^2 \sin ^2 30^{\circ}}{2(10)}\) \(=5\)
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