NEET · Physics · STD 11 - 12 . kinetic theory of gases
A container has two chambers of volumes \(V_1=2\) litres and \(V_2=3\) litres separated by a partition made of a thermal insulator. The chambers contains \(n_1=5\) and \(n_2=4\) moles of ideal gas at pressures \(p_1=1 atm\) and \(p_2=2 atm\), respectively. When the partition is removed, the mixture attains an equilibrium pressure of:
- A 1.3 atm
- B 1.6 atm
- C 1.4 atm
- D 1.8 atm
Answer & Solution
Correct Answer
(B) 1.6 atm
Step-by-step Solution
Detailed explanation
By energy conservation
\(E _1+ E _2= E _{\operatorname{mix}} \)
\( \frac{n _1 f _1 RT _1}{2}+\frac{n _2 f _2 RT _2}{2}=\frac{\left( n _1 \times n _2\right) fRT _{\operatorname{mix}}}{2} \)
\( \Rightarrow \frac{3}{2} P _1 V_1+\frac{3}{2} P _2 V_2=\frac{3}{2} P _{\operatorname{mix}}\left( V _1+ V _2\right) \)
\( \frac{3}{2} \times 1 \times 2+\frac{3}{2} \times 2 \times 3=\frac{3}{2} \times P _{\operatorname{mix}}(5) \)
\( \therefore P _{\operatorname{mix}}=\frac{8}{5} \)
\( P _{\operatorname{mix}}=1.6 atm\)
\(E _1+ E _2= E _{\operatorname{mix}} \)
\( \frac{n _1 f _1 RT _1}{2}+\frac{n _2 f _2 RT _2}{2}=\frac{\left( n _1 \times n _2\right) fRT _{\operatorname{mix}}}{2} \)
\( \Rightarrow \frac{3}{2} P _1 V_1+\frac{3}{2} P _2 V_2=\frac{3}{2} P _{\operatorname{mix}}\left( V _1+ V _2\right) \)
\( \frac{3}{2} \times 1 \times 2+\frac{3}{2} \times 2 \times 3=\frac{3}{2} \times P _{\operatorname{mix}}(5) \)
\( \therefore P _{\operatorname{mix}}=\frac{8}{5} \)
\( P _{\operatorname{mix}}=1.6 atm\)
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