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NEET · Physics · STD 12 -7. Alternating current
A circuit when connected to an \(A.C.\) source of \(12\; V\) gives a current of \(0.2\; A\). The same circuit when connected to a \(D.C.\) source of \(12\; V\), glves a current of \(0.4\; A\). The circuit is
- A series \(LR\)
- B series \(RC\)
- C series \(LC\)
- D series \(LCR\)
Answer & Solution
Correct Answer
(A) series \(LR\)
Step-by-step Solution
Detailed explanation
\(Z=\frac{12}{0.2}=60 \Omega\) and \(\mathrm{R}=\frac{12}{0.4}=30 \Omega\) In D.C Source Capacitor a would provide Infinite resistance but current is present in the given circuit. it means resistor and Inductor are in circuit
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