NEET · Physics · STD 11 - 3.2 motion in plane
A bullet is fired from a gun at the speed of \(280\,ms ^{-1}\) in the direction \(30^{\circ}\) above the horizontal. The maximum height attained by the bullet is \(........\,m\) \(\left(g=9.8\,ms ^{-2}, \sin 30^{\circ}=0.5\right):-\)
- A \(3000\)
- B \(2800\)
- C \(2000\)
- D \(1000\)
Answer & Solution
Correct Answer
(D) \(1000\)
Step-by-step Solution
Detailed explanation
\(H _{\max }=\frac{ u ^2 \sin ^2 \theta}{2 g }\) \(=\frac{(280)^2\left(\sin 30^{\circ}\right)^2}{2(9.8)}\)
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