NEET · Physics · STD 11 - 3.2 motion in plane
A bob is whirled in a horizontal plane by means of a string with an initial speed of \(\omega \mathrm{rpm}\). The tension in the string is \(T\). If speed becomes \(2 \omega\) while keeping the same radius, the tension in the string becomes:
- A \(4 T\)
- B \(\frac{T}{4}\)
- C \(\sqrt{2} T\)
- D \(T\)
Answer & Solution
Correct Answer
(A) \(4 T\)
Step-by-step Solution
Detailed explanation
(image) \(T=m / \omega^2\)
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