NEET · Physics · STD 11 - 10.2 transmission of heat
A black body is at a temperature of \(5760\ K\). The energy of radiation emitted by the body at wavelength \(250\ nm\) is \(U_1\), at wavelength \(500\ nm\) is \(U_2\) and that at \(1000\ nm\) is \(U_3\). Wien's constant, \(b = 2.88 \times 10^6\ nm\ K\). Which of the following is correct?
- A \(U_3=0\)
- B \(U_1>U_2\)
- C \(U_2>U_1\)
- D \(U_1=0\)
Answer & Solution
Correct Answer
(C) \(U_2>U_1\)
Step-by-step Solution
Detailed explanation
According to \(Wein's\) displacement law \({\lambda _m} = \frac{b}{T} = \frac{{2.88 \times {{10}^6}\,nm\,K}}{{5760\,K}} = 500\,nm\)
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