NEET · Physics · STD 11 - 4.1 newtons laws of motion
A ball of mass \(0.15\, \mathrm{~kg}\) is dropped from a height \(10\, \mathrm{~m}\), strikes the ground and rebounds to the same height. The magnitude of impulse imparted to the ball is \(\left(\mathrm{g}=10 \,\mathrm{~m} / \mathrm{s}^{2}\right)\) nearly : (In \(\mathrm{kg}\, \mathrm{m} / \mathrm{s}\))
- A \(0\)
- B \(4.2\)
- C \(2.1\)
- D \(1.4\)
Answer & Solution
Correct Answer
(B) \(4.2\)
Step-by-step Solution
Detailed explanation
\(v=\sqrt{2 g h}\) \(v=\sqrt{2 \times 10 \times 10}\)
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