NEET · Physics · STD 11 - 3.2 motion in plane

A ball is projected with a velocity, \(10 ms ^{-1}\), at an angle of \(60^{\circ}\) with the vertical direction. Its speed at the highest point of its trajectory will be\(............... ms ^{-1}\)

A \(5 \sqrt{3}\)
B \(5\)
C \(10\)
D Zero

Verified Solution

Answer & Solution

Correct Answer

(A) \(5 \sqrt{3}\)

Step-by-step Solution

Detailed explanation

At highest point only horizontal component of velocity remains \(\Rightarrow u _{ x }= u \cos \theta\) \(u _{ x }= u \cos \theta =10 \cos 30^{\circ}\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Match List\(-I\) With List\(-II\)

\((a)\) Gravitational constant \((G)\)	\((i)\) \(\left[ L ^{2} T ^{-2}\right]\)
\((b)\) Gravitational potential energy	\((ii)\) \(\left[ M ^{-1} L ^{3} T ^{-2}\right]\)
\((c)\) Gravitational potential	\((iii)\) \(\left[ LT ^{-2}\right]\)
\((d)\) Gravitational intensity	\((iv)\) \(\left[ ML ^{2} T ^{-2}\right]\)

Choose the correct answer from the options given below:

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