When initial concentration of a reactant is doubled in a reaction, its half-life period is not affected. The order of the reaction is

A second
B more than zero but less than first
C zero
D first.

Verified Solution

Answer & Solution

Correct Answer

(D) first.

Step-by-step Solution

Detailed explanation

\(T_{1 / 2}\) for first order reaction is independent from initial concentration of reactions \(T_{1 / 2}=\frac{\ln \,2}{k}\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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From NEET

Match List I with List II:

\(\text{List - I (Ion)}\)	\(\text{List - II (Group Number}\) \(\text{in Cation Analysis)}\)
A. \(\text{Co} ^{2+}\)	(I) \(\text{Group - I}\)
B. \(\text{Mg} ^{2+}\)	(II) \(\text{Group - III}\)
C. \(\text{Pb} ^{2+}\)	(III) \(\text{Group - IV}\)
D. \(\text{Al} ^{3+}\)	(IV) \(\text{Group - VI}\)

NEET 2025 Medium

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