NEET · Chemistry · STD 11 - 1. Some basic concept of chemistry
What mass of \(95\, \%\) pure \(CaCO _{3}\) will be required to neutralise \(50 \,mL\) of \(0.5\, M \,HCl\) solution according to the following reaction? (In \(g\)) \(CaCO _{3( s )}+2 HCl _{( aq )} \rightarrow \)\(CaCl _{2( aq )}+ CO _{2( g )}+2 H _{2} O _{( l )}\) [Calculate upto second place of decimal point]
- A \(1.32\)
- B \(3.65\)
- C \(9.50\)
- D \(1.25\)
Answer & Solution
Correct Answer
(A) \(1.32\)
Step-by-step Solution
Detailed explanation
\(CaCO _{3(s)}+2 HCl _{(\text {aq) })} \rightarrow \)\(CaCl _{2(a q)}+ CO _{2(q)}+ H _{2} O _{(q)}\) no. of moles of \(CaCO _{3}\) (pure) \(=\frac{1}{2} \times\) mole of \(HCl\)
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